In addition, we have thought one $C”(q) > 0$ (i

In addition, we have thought one $C”(q) > 0$ (i And this, if the $p$ grows, $C'(q^*)$ grows. elizabeth. $C'(q)$ is precisely expanding into the $q$ ). Hence, in the event the $p$ and therefore $C'(q^*)$ develops, it should even be one $q^*$ grows. QED. I happened to be merely looking to understand why me, […]